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I can't figure out this stoichiometry problem: how many grams of H2O are produced when 5 grams of H2 reacts with excess O2?

Here's the step-by-step: Step 1: Write the balanced equation 2H₂ + O₂ → 2H₂O Step 2: Convert grams of H₂ to moles 5g ÷ 2g/mol = 2.5 mol H₂ Step 3: Use mole ratio Ratio is 2H₂ : 2H₂O = 1:1 So 2.5 mol H₂ → 2.5 mol H₂O Step 4: Convert mol H₂O to grams 2.5 mol × 18g/mol = 45 grams H₂O ✅ Answer: 45 grams of water are produced.

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